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| Exercise 3.2

Question 1

Solve the following pair of linear equations by the substitution method.

(i) x+y=14x + y = 14 xy=4x - y = 4

(ii) st=3s - t = 3 6s+2t=36s + 2t = 3

(iii) 3xy=33x - y = 3 9x3y=99x - 3y = 9

(iv) 0.2x+0.3y=1.30.2x + 0.3y = 1.3 0.4x+0.5y=2.30.4x + 0.5y = 2.3

(v) 2x+3y=02x + 3y = 0 3x8y=03x - 8y = 0

(vi) 3x+5y=223x + 5y = 22 3x2y=63x - 2y = 6

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