In Fig. 6.18, if LM \parallel CB and LN \parallel CD, prove that \displaystyle \frac{AM}{AN} = \frac{AB}{AD} = \frac{LM}{LN}\,.

Question

In Fig. 6.18, if $LM \parallel CB$ and $LN \parallel CD$, prove that $\displaystyle \frac{AM}{AN} = \frac{AB}{AD} = \frac{LM}{LN}\,. $

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