In Fig. 6.35, △ODC∼△OBA\triangle ODC \sim \triangle OBA△ODC∼△OBA, ∠BOC=125∘\angle BOC = 125^\circ∠BOC=125∘ and ∠CDO=70∘\angle CDO = 70^\circ∠CDO=70∘. Find ∠DOC\angle DOC∠DOC, ∠DCO\angle DCO∠DCO and ∠OAB\angle OAB∠OAB.