In △ABC\triangle ABC△ABC, right-angled at BBB, if tanA=13\tan A = \dfrac{1}{3}tanA=31, find the value of: (i) sinAcosC+cosAsinC\sin A \cos C + \cos A \sin CsinAcosC+cosAsinC (ii) cosAcosC−sinAsinC\cos A \cos C - \sin A \sin CcosAcosC−sinAsinC