In Fig. 10.11, if TPTPTP and TQTQTQ are the two tangents to a circle with centre OOO so that ∠POQ=110∘\angle POQ = 110^\circ∠POQ=110∘, then ∠PTQ\angle PTQ∠PTQ is equal to
(A) 60∘60^\circ60∘ (B) 70∘70^\circ70∘ (C) 80∘80^\circ80∘ (D) 90∘90^\circ90∘