Question 22

Refer to Example 13.

(i) Complete the following table:

$$\begin{array}{|c|c|c|c|c|c|c|c|c|c|c|c|}

\hline
\text{Event: 'Sum on 2 dice'} & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 & 11 & 12 \\
\hline
\text{Probability} & \dfrac{1}{36} & \dfrac{1}{18} & \dfrac{1}{12} & \dfrac{5}{36} & \dfrac{5}{18} & \dfrac{7}{36} & \dfrac{5}{18} & \dfrac{5}{36} & \dfrac{1}{12} & \dfrac{1}{18} & \dfrac{1}{36} \\
\hline
\end{array}$$

(ii) A student argues that ‘there are 11 possible outcomes 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12. Therefore, each of them has a probability $\dfrac{1}{11}$. Do you agree with this argument? Justify your answer.