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Exercise 13.3

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Problems
7 total
Q1

The following frequency distribution gives the monthly consumption of electricity of 68 consumers of a locality. Find the median, mean and mode of the data and compare them.

Monthly consumption (in units)Number of consumers65 – 85485 – 1055105 – 12513125 – 14520145 – 16514165 – 1858185 – 2054
\begin{array}{|c|c|}

\hline
\text{Monthly consumption (in units)} & \text{Number of consumers} \\
\hline
65\text{ – }85   & 4  \\
85\text{ – }105  & 5  \\
105\text{ – }125 & 13 \\
125\text{ – }145 & 20 \\
145\text{ – }165 & 14 \\
165\text{ – }185 & 8  \\
185\text{ – }205 & 4  \\
\hline
\end{array}
Pending
Q2

If the median of the distribution given below is 28.528.5, find the values of xx and yy.

Class intervalFrequency01051020x2030203040154050y50605Total60
\begin{array}{|c|c|}

\hline
\text{Class interval} & \text{Frequency} \\
\hline
0 - 10 & 5 \\
\hline
10 - 20 & x \\
\hline
20 - 30 & 20 \\
\hline
30 - 40 & 15 \\
\hline
40 - 50 & y \\
\hline
50 - 60 & 5 \\
\hline
\text{Total} & 60 \\
\hline
\end{array}
Pending
Q3

A life insurance agent found the following data for distribution of ages of 100 policy holders.
Calculate the median age, if policies are given only to persons having age 1818 years onwards but less than 6060 years.

Age (in years)Number of policy holders (cumulative)Below 202Below 256Below 3024Below 3545Below 4078Below 4589Below 5092Below 5598Below 60100
\begin{array}{|c|c|}

\hline
\text{Age (in years)} & \text{Number of policy holders (cumulative)}\\
\hline
\text{Below }20 & 2\\
\hline
\text{Below }25 & 6\\
\hline
\text{Below }30 & 24\\
\hline
\text{Below }35 & 45\\
\hline
\text{Below }40 & 78\\
\hline
\text{Below }45 & 89\\
\hline
\text{Below }50 & 92\\
\hline
\text{Below }55 & 98\\
\hline
\text{Below }60 & 100\\
\hline
\end{array}
Pending
Q4

The lengths of 40 leaves of a plant are measured correct to the nearest millimetre, and the data obtained is represented in the following table:

Length (in mm)Number of leaves11812631271355136144914515312154162516317141721802
\begin{array}{|c|c|}

\hline
\text{Length (in mm)} & \text{Number of leaves} \\
\hline
118 - 126 & 3 \\
\hline
127 - 135 & 5 \\
\hline
136 - 144 & 9 \\
\hline
145 - 153 & 12 \\
\hline
154 - 162 & 5 \\
\hline
163 - 171 & 4 \\
\hline
172 - 180 & 2 \\
\hline
\end{array}

Find the median length of the leaves.

(Hint: The data needs to be converted to continuous classes for finding the median, since the formula assumes continuous classes. The classes then change to 117.5126.5117.5 - 126.5, 126.5135.5126.5 - 135.5, \dots, 171.5180.5171.5 - 180.5.)

Pending
Q5

The following table gives the distribution of the life time of 400 neon lamps:

Life time (in hours)Number of lamps1500200014200025005625003000603000350086350040007440004500624500500048
\begin{array}{|c|c|}

\hline
\text{Life time (in hours)} & \text{Number of lamps} \\
\hline
1500 - 2000 & 14 \\
\hline
2000 - 2500 & 56 \\
\hline
2500 - 3000 & 60 \\
\hline
3000 - 3500 & 86 \\
\hline
3500 - 4000 & 74 \\
\hline
4000 - 4500 & 62 \\
\hline
4500 - 5000 & 48 \\
\hline
\end{array}

Find the median life time of a lamp.

Pending
Q6

100 surnames were randomly picked up from a local telephone directory and the frequency distribution of the number of letters in the English alphabets in the surnames was obtained as follows:

Number of letters1447710101313161619Number of surnames630401644
\begin{array}{|c|c|c|c|c|c|c|}

\hline
\text{Number of letters} & 1 - 4 & 4 - 7 & 7 - 10 & 10 - 13 & 13 - 16 & 16 - 19 \\
\hline
\text{Number of surnames} & 6 & 30 & 40 & 16 & 4 & 4 \\
\hline
\end{array}

Determine the median number of letters in the surnames. Find the mean number of letters in the surnames? Also, find the modal size of the surnames.

Pending
Q7

The distribution below gives the weights of 30 students of a class. Find the median weight of the students.

Weight (in kg)4045455050555560606565707075Number of students2386632
\begin{array}{|c|c|c|c|c|c|c|c|}

\hline
\text{Weight (in kg)} & 40 - 45 & 45 - 50 & 50 - 55 & 55 - 60 & 60 - 65 & 65 - 70 & 70 - 75 \\
\hline
\text{Number of students} & 2 & 3 & 8 & 6 & 6 & 3 & 2 \\
\hline
\end{array}
Pending