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Introduction To Trigonometry

Exercise 8.2

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Problems
4 total
Q1

Evaluate the following :

(i) sin⁡60∘cos⁡30∘+sin⁡30∘cos⁡60∘\sin 60^\circ \cos 30^\circ + \sin 30^\circ \cos 60^\circ

(ii) 2tan⁡245∘+cos⁡230∘−sin⁡260∘2 \tan^2 45^\circ + \cos^2 30^\circ - \sin^2 60^\circ

(iii) cos⁡45∘sec⁡30∘+csc⁡30∘\dfrac{\cos 45^\circ}{\sec 30^\circ} + \csc 30^\circ

(iv) sin⁡30∘+tan⁡45∘−csc⁡60∘sec⁡30∘+cos⁡60∘+cot⁡45∘\dfrac{\sin 30^\circ + \tan 45^\circ - \csc 60^\circ}{\sec 30^\circ + \cos 60^\circ + \cot 45^\circ}

(v) 2sin⁡60∘+5cos⁡60∘4sec⁡30∘−tan⁡45∘+sin⁡30∘cos⁡30∘\dfrac{2 \sin 60^\circ + 5 \cos 60^\circ}{4 \sec 30^\circ - \tan 45^\circ} + \dfrac{\sin 30^\circ}{\cos 30^\circ}

Pending
Q2

Choose the correct option and justify your choice :

(i) 2tan⁡30∘1+tan⁡230∘=\dfrac{2\tan 30^\circ}{1+\tan^2 30^\circ} = (A) sin⁡60∘\sin 60^\circ    (B) cos⁡60∘\cos 60^\circ    (C) tan⁡60∘\tan 60^\circ    (D) sin⁡30∘\sin 30^\circ

(ii) 1−tan⁡45∘1+tan⁡45∘=\dfrac{1-\tan 45^\circ}{1+\tan 45^\circ} = (A) tan⁡90∘\tan 90^\circ    (B) 11    (C) sin⁡45∘\sin 45^\circ    (D) 00

(iii) sin⁡2A=2sin⁡A\sin 2A = 2 \sin A is true when A=A = (A) 0∘0^\circ    (B) 30∘30^\circ    (C) 45∘45^\circ    (D) 60∘60^\circ

(iv) 2tan⁡30∘1−tan⁡230∘=\dfrac{2\tan 30^\circ}{1-\tan^2 30^\circ} = (A) cos⁡60∘\cos 60^\circ    (B) sin⁡60∘\sin 60^\circ    (C) tan⁡60∘\tan 60^\circ    (D) sin⁡30∘\sin 30^\circ

Pending
Q3

If tan⁡(A+B)=3\tan (A + B) = \sqrt{3} and tan⁡(A−B)=13\tan (A - B) = \dfrac{1}{\sqrt{3}}; 0∘<A+B≤90∘0^\circ < A + B \le 90^\circ; A>BA > B, find AA and BB.

Pending
Q4

State whether the following are true or false. Justify your answer.

(i) sin⁡(A+B)=sin⁡A+sin⁡B\sin(A + B) = \sin A + \sin B.

(ii) The value of sin⁡θ\sin \theta increases as θ\theta increases.

(iii) The value of cos⁡θ\cos \theta increases as θ\theta increases.

(iv) sin⁡θ=cos⁡θ\sin \theta = \cos \theta for all values of θ\theta.

(v) cot⁡A\cot A is not defined for A=0∘A = 0^\circ.

Pending